3y-2[y-3(2-3y)+5]=18

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Solution for 3y-2[y-3(2-3y)+5]=18 equation:


Simplifying
3y + -2[y + -3(2 + -3y) + 5] = 18
3y + -2[y + (2 * -3 + -3y * -3) + 5] = 18
3y + -2[y + (-6 + 9y) + 5] = 18

Reorder the terms:
3y + -2[-6 + 5 + y + 9y] = 18

Combine like terms: -6 + 5 = -1
3y + -2[-1 + y + 9y] = 18

Combine like terms: y + 9y = 10y
3y + -2[-1 + 10y] = 18
3y + [-1 * -2 + 10y * -2] = 18
3y + [2 + -20y] = 18

Reorder the terms:
2 + 3y + -20y = 18

Combine like terms: 3y + -20y = -17y
2 + -17y = 18

Solving
2 + -17y = 18

Solving for variable 'y'.

Move all terms containing y to the left, all other terms to the right.

Add '-2' to each side of the equation.
2 + -2 + -17y = 18 + -2

Combine like terms: 2 + -2 = 0
0 + -17y = 18 + -2
-17y = 18 + -2

Combine like terms: 18 + -2 = 16
-17y = 16

Divide each side by '-17'.
y = -0.9411764706

Simplifying
y = -0.9411764706

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